Diamond Q&A

In this section of the site, I publish some interesting private exchanges I have had with readers of the site who have contacted me via the “Ask a Question” form. I believe you will find that the questions and answers are both interesting and educational. Of course, names have been removed to preserve privacy.

Use the filter below to find Q&As relevant to your diamond search:

  Returns results

Q&A: Looking for a 1 Ct. Princess Cut Diamond With Around $5k Budget

I am looking for a 1 carat princess cut with a budget under 5k. Do you have any recommendations?  I’d be happy to make some recommendations and guide you through the process. What type of setting are you considering? Yellow gold or white gold/platinum? Will it be a solitaire or does it have sidestones/pave? This …

Q&A: Choosing a Round Stone for a White Metal Engagement Ring with $5k Total Budget

(1) Would like to keep band + stone under $5k; looking for round stone (2) Platinum or white gold (3) example of band I am looking for http://www.ethanlord.com/engagement-rings/diamond-rings/petite-shared-prong-scalloped.html       Here is my recommendation: http://www.jamesallen.com/engagement-rings/pave/-18k-white-gold-2.0mm-art-nouveau-pave-set-diamond-engagement-ring-item-9023?a_aid=dmnd1357 www.jamesallen.com/loose-diamonds/round-cut/0.90-carat-i-color-si1-clarity-excellent-cut-sku-276128?a_aid=dmnd1357 This is a fantastic combo. The diamond is bright, superbly cut and eye-clean (the inclusion is right on the …

Q&A: Looking for a 1.75-1.9 Ct. Round Diamond With $15k Total Budget

Hi, I am currently looking for a GIA/AGL diamond that is Carat: 1.75-1.9 Color: I or Higher Clarity: SI1 or Higher Cut:Excellent/Ideal Polish/Symmetry: excellent Flurescence: Medium is acceptable My budget is $12000 for the diamond and 15,000 for the total ring including the band. Here is an example of I diamond I am looking at http://www.bluenile.com/build-your-own-diamond-ring?action=remove&forceStep=DIAMONDS_STEP#diamonds_forceStep=DIAMONDS_STEP|builder=BYOR|pid=LD03872524 And …

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